MCQ
The equation of the normal at the point $(a\sec \theta ,\;b\tan \theta )$ of the curve ${b^2}{x^2} - {a^2}{y^2} = {a^2}{b^2}$ is
  • A
    $\frac{{ax}}{{\cos \theta }} + \frac{{by}}{{\sin \theta }} = {a^2} + {b^2}$
  • B
    $\frac{{ax}}{{\tan \theta }} + \frac{{by}}{{\sec \theta }} = {a^2} + {b^2}$
  • $\frac{{ax}}{{\sec \theta }} + \frac{{by}}{{\tan \theta }} = {a^2} + {b^2}$
  • D
    $\frac{{ax}}{{\sec \theta }} + \frac{{by}}{{\tan \theta }} = {a^2} - {b^2}$

Answer

Correct option: C.
$\frac{{ax}}{{\sec \theta }} + \frac{{by}}{{\tan \theta }} = {a^2} + {b^2}$
c
(c) Equation of normal to hyperbola $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$ at $(a\sec \theta ,b\tan \theta )$ is

$\frac{{{a^2}x}}{{a\sec \theta }} + \frac{{{b^2}y}}{{b\tan \theta }} = {a^2} + {b^2}$.

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