The equation of the normal at the point ( a 4 , ;a ) to the parab… - Vidyadip

MCQ

The equation of the normal at the point $\left( {\frac{a}{4},\;a} \right)$ to the parabola ${y^2} = 4ax$, is

A
$4x + 8y + 9a = 0$
✓
$4x + 8y - 9a = 0$
C
$4x + y - a = 0$
D
$4x - y + a = 0$

✓

Answer

Correct option: B.

$4x + 8y - 9a = 0$

b
(b) $y - a =$$ -a\over{2a}$$(x - {a\over4})$

=> $2y + x = 2a + \frac{a}{4} = \frac{{9a}}{4}$

=> $2y + x - \frac{{9a}}{4} = 0$

$i.e.$, $4x + 8y - 9a = 0$.

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