MCQ
The equilibrium constant for the reaction

$\mathrm{SO}_3(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})$

is $\mathrm{K}_{\mathrm{C}}=4.9 \times 10^{-2}$. The value of $\mathrm{K}_{\mathrm{C}}$ for the reaction given below is

$2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})$ is

  • A
    $4.9$
  • B
    $41.6$
  • $49$
  • D
    $416$

Answer

Correct option: C.
$49$
c
$\mathrm{K}_{\mathrm{C}}^{\prime}=\left(\frac{1}{\mathrm{~K}_{\mathrm{C}}}\right)^2=\left(\frac{1}{4.9 \times 10^{-2}}\right)^2$

$\mathrm{~K}_{\mathrm{C}}^{\prime}=416.49$

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