MCQ
The equilibrium constant for the reaction
$\mathrm{SO}_3(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})$
is $\mathrm{K}_{\mathrm{C}}=4.9 \times 10^{-2}$. The value of $\mathrm{K}_{\mathrm{C}}$ for the reaction given below is
$2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})$ is
- A$4.9$
- B$41.6$
- ✓$49$
- D$416$