MCQ
The equilibrium constant for the reaction
$S{O_{3(g)}} \rightleftharpoons S{O_{2(g)}} + 1/2\,{O_{2(g)}}$ is $4.9 \times 10^{-2}$ then find equilibrium constant for the reaction
$2S{O_{2(g)}} + {O_{2(g)}} \rightleftharpoons 2SO_3(g)$
- ✓$416$
- B$2.40 \times {10^{ - 3}}$
- C$9.8 \times {10^{ - 2}}$
- D$4.9 \times {10^{ - 2}}$