MCQ
The equilibrium constant $(K_c)$ for the reaction,

$CaS{O_4}.5{H_2}{O_{(s)}}\, \rightleftharpoons \,CaS{O_4}.3{H_2}{O_{(s)}} + 2{H_2}{O_{(g)}}$ is equal to

  • A
    $[H_2O]^2$
  • B
    $\frac{{\left[ {CaS{O_4}.3{H_2}O} \right]}}{{\left[ {CaS{O_4}.5{H_2}O} \right]}}$
  • $[H_2O]$
  • D
    $\frac{{\left[ {CaS{O_4}.3{H_2}O} \right]{{\left[ {{H_2}O} \right]}^2}}}{{\left[ {CaS{O_4}.5{H_2}O} \right]}}$

Answer

Correct option: C.
$[H_2O]$
c
$K_c = [H_2O]^2$. Solid phases are not to be reported

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free