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6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
The equilibrium constant $(K_c) $ for the reaction ${\rm{HA}} + {\rm{B}}$ $\rightleftharpoons$ ${\rm{B}}{{\rm{H}}^+} + {{\rm{A}}^-}$ is $100$. If the rate constant for the forward reaction is $10^5$, then rate constant for the backward reaction is
  • A
    ${10^7}$
  • ✓
    ${10^3}$
  • C
    ${10^{ - 3}}$
  • D
    ${10^{ - 5}}$
✓

Answer

Correct option: B.
${10^3}$
(b) ${K_c} = \frac{{{K_f}}}{{{K_b}}}\,\,\therefore \,{K_b} = \frac{{{K_f}}}{{{K_c}}} = \frac{{{{10}^5}}}{{100}} = {10^3}$

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