MCQ
The equivalent capacitance between points $A$ and $B$ in below shown figure will be..........$\mu F$.


- A$9$
- B$60$
- ✓$6$
- D$79$

Finally equivalent capacitance
$=\frac{24 \times 8}{24+8}=\frac{24 \times 8}{32}=6 \mu F$
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Reason : Two equipotential surfaces are parallel to each other.
$\rho=\left\{\begin{array}{l}\rho_0 \text { for } r \leq R \\ 0 \text { for } r>R\end{array}\right.$
where $\rho_0$ is a constant. A test mass can undergo circular motion under the influence of the gravitational field of particles. Its speed $V$ as a function of distance $\mathrm{r}(0<\mathrm{r}<\infty)$ from the centre of the system is represented by

