Question
The equivalent capacitance of the combination shown in figure is:
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Answer
Since the potential at point $A$ is equal to the potential at point $B,$ no current will flow along arm $AB.$
Hence, the capacitor on arm $AB$ will not contribute to the circuit.
Also, because the remaining two capacitors are connected in parallel, the net capacitance of the circuit is given by
$C_{eq} = C + C = 2C$
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