MCQ
The equivalent resistance across $AB$ would be ............ $\Omega$


- ✓$6$
- B$8$
- C$12$
- D$20$

$\boxed{{{\text{R}}_{{\text{eq}}}} = \frac{{9 \times 18}}{{27}} = 6\,\Omega }$
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(mass of proton $=1.67 \times 10^{-27} \,kg ,$ charge of the proton $\left.=1.6 \times 10^{-19}\, C \right)$
Reason : Neutrons are slightly more massive than protons.