MCQ
The exothermic formation of $ClF_3$ is represented by the equation

$C{l_{2\left( g \right)}} + 3{F_2}_{\left( g \right)} \rightleftharpoons 2C{l_3}_{\left( g \right)};\Delta {H_r} =  - 329\,kJ$ 

Which of the following will increase the quantity of $ClF_3$ in an equilibrium mixture of $Cl_2, F_2$ and $ClF_3$ ?

  • A
    Removing $Cl_2$
  • B
    Increasing the temperature
  • C
    Adding inert gas at constant volume
  • Decreasing the volume of the container

Answer

Correct option: D.
Decreasing the volume of the container
d
The reaction given is an exothermic reaction thus according to lechatalier's principle lowering of temp, addition of $f_2$ and or $Cl_2$ favour for the forward direction and hence the production of $ClF_3$

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