MCQ
The expression $\left( {\frac{1}{{\sqrt 2 }}\hat i + \frac{1}{{\sqrt 2 }}\hat j} \right)$ is a
  • Unit vector
  • B
    Null vector
  • C
    Vector of magnitude $\sqrt 2 $
  • D
    Scalar

Answer

Correct option: A.
Unit vector
a
(a) $\vec P = \frac{1}{{\sqrt 2 }}\hat i + \frac{1}{{\sqrt 2 }}\hat j$

$|\vec P| = \sqrt {{{\left( {\frac{1}{{\sqrt 2 }}} \right)}^2} + {{\left( {\frac{1}{{\sqrt 2 }}} \right)}^2}} = 1$

It is a unit vector.

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