MCQ
The $\text{F}-\text{B}-\text{F}$ bond angle in BF3 molecule is:
- A90°
- B109.5°
- C120°
- D180°
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(Given) $\Delta H^o_f (CaCO_3,s) = -1207 \, \frac{kJ}{mol}$
$\Delta H^o_f \,(CaO,s) = -635 \,kJ/mol$
$\Delta H^o_f \,(CO_2.g) = -394 \,kJ/mol$