MCQ
The false statement in the following is
  • A
    $\mathrm{p} \wedge(\sim \mathrm{p})$ is a contradiction
  • B
    $\mathrm{p} \vee(\sim \mathrm{p})$ is a tautology
  • C
    $\sim(\sim p) \leftrightarrow p$ is tautology
  • $(\mathrm{p} \rightarrow \mathrm{q}) \leftrightarrow(\sim \mathrm{q} \rightarrow \sim \mathrm{p})$ is a contradiction

Answer

Correct option: D.
$(\mathrm{p} \rightarrow \mathrm{q}) \leftrightarrow(\sim \mathrm{q} \rightarrow \sim \mathrm{p})$ is a contradiction
(D) $p \rightarrow q$ is logically equivalent to $\sim q \rightarrow \sim p$
$\therefore \quad(p \rightarrow q) \leftrightarrow(\sim q \rightarrow \sim p)$ is a tautology
...[Using Shortcut 8]
But, it is given contradiction.
Hence, it is false statement.

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