
==> $\int_{\,{r_1}}^{\,{r_2}} {\frac{{dr}}{{{r^2}}} = - \frac{{4\pi K}}{H}\int_{\,{T_1}}^{{T_1}} {dT} } $
Which on integration and simplification gives
$H = \frac{{dQ}}{{dt}} = \frac{{4\pi K{r_1}{r_2}({T_1} - {T_2})}}{{{r_2} - {r_1}}}$
==> $\frac{{dQ}}{{dt}} \propto \frac{{{r_1}{r_2}}}{{({r_2} - {r_1})}}$

