MCQ
The final product formed when ethyl bromide is treated with excess of alcoholic $KOH$ is
- ✓Ethylene
- BEthane
- CEthyne
- DVinyl bromide
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$2P(s) + 3C{l_2}(g)\,\, \to \,\,2PC{l_3}(l);\,\Delta H = - 151.8\,kcal$
$PC{l_3}(l) + C{l_2}(g)\,\, \to \,\,PC{l_5}(s);\,\,\Delta H = - 32.8\,kcal$
......$kcal$