MCQ
The final product of the given sequence is :


- A

- B

- C

- ✓








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The Gibbs free energy change for the above reaction at $298\, K$ is $x \times 10^{-1} \,k\,J\, mol ^{-1}$;
The value of $x$ is ..... [nearest integer]$\left [\text { Given : } E _{ Cu ^{2} / / Cu }=0.34\, V ; E _{ Sn ^{2} / Sn }^{\ominus}=-0.14 \,V ; F=96500\, C\, mol ^{-1}\right]$

Reason : Oxidation takes place at anode and reduction at cathode.
$(I)$ Glucose
$(II)$ Fructose
$(III)$ Maltose
$(IV)$ Sucrose
$(V)$ Galactose