MCQ
The first four $I.E.$ values of an element are $284, 412, 656$ and $3210\, k.J\, mol^{-1}.$  The number of valence electrons in the element are
  • A
    $1$
  • B
    $2$
  • $3$
  • D
    $4$

Answer

Correct option: C.
$3$
c
Considering the first four I.E values. of elements, the $I.E._4$ value of element is high and the difference between $I.E._3$ and $I.E._4$ is very High.

$I \cdot E_2-I E_1=412-284=128 \cdot kJ / mol$

$I \cdot E_3-I \cdot E_2=654-412=242 kJ / mol$

$I \cdot E_4-I \cdot E_3=3210-656=2554 kJ / mol$.

The avalue of $2554\,kJ/mol$ is the differeace between $I-E_4$ and $I-E_3$ suggest that the element is not able to loose its electron After loosing the three election. i.e the element will become stable on loss of three electrons.

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