MCQ
The first resonance length of a resonance tube is $40\,\, cm$ and the second resonance length is $122\,\, cm$. The third resonance length of the tube will be... $cm$
- A$200$
- B$202$
- C$203$
- ✓$204$
✓
Answer
Correct option: D.
$204$
d
$\frac{\lambda}{2}=122-40=82 \mathrm{cm}$
$\frac{\lambda}{2}=122-40=82 \mathrm{cm}$
$\therefore$ Next resonance length $=122 \mathrm{cm}+82 \mathrm{cm}$
$=204 \mathrm{cm}$
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