Question
The first term a and common difference d are given. Find first four terms of A.P :

$a=8, d=-5$

Answer


$\begin{array}{l} a=8, d=-5 \\
a=t_1=8 \\
t_2=t_1+d=8+(-5)=3 \\
t_3=t_2+d=3+(-5)=-2 \\
t_4=t_3+d=-2+(-5)=-7 \\
8,3,-2,-7, \ldots \\
\therefore \text { A.P. is }=8,3,-2,-7, \ldots
\end{array}
$

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