Download App

6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
The following equilibria are given :
$N_2 + 3H_2  \rightleftharpoons  2NH_3 ; K_1$
$N_2 + O_2  \rightleftharpoons  2NO ; K_2$
$H_2 + \frac{1}{2}O_2  \rightleftharpoons  H_2O; K_3$

The equilibrium constant of the reaction $2N{H_3} + \frac{5}{2}{O_2} \rightleftharpoons 2NO + 3{H_2}O$ in terms of $K_1, K_2$ and $K_3$ is

  • A
    $\frac{{{K_1}{K_2}}}{{{K_3}}}$
  • B
    $\frac{{{K_1}K_3^2}}{{{K_2}}}$
  • ✓
    $\frac{{{K_2}K_3^3}}{{{K_1}}}$
  • D
    $K_1K_2K_3$
✓

Answer

Correct option: C.
$\frac{{{K_2}K_3^3}}{{{K_1}}}$
c
$(I)\,{N_2} + 3{H_2} \leftrightarrow 2N{H_3};$

               ${K_1} = \frac{{{{[N{H_3}]}^2}}}{{[{N_2}]{{[{H_2}]}^3}}}$

$(II)\,{N_2} + {O_2} \leftrightarrow 2NO;$

               ${K_2} = \frac{{{{[NO]}^2}}}{{[{N_2}][{O_2}]}}$

$(III)\,{H_2} + \frac{1}{2}{O_2} \leftrightarrow {H_2}O;$

               ${K_3} = \frac{{[{H_2}O]}}{{[{H_2}]{{[{O_2}]}^{1/2}}}}$

$(IV)\,2N{H_3} + \frac{5}{2}{O_2} \leftrightarrow 2NO + 3{H_2}O$

               ${K_c} = \frac{{{{[NO]}^2}{{[{H_2}O]}^3}}}{{{{[N{H_3}]}^2}{{[{O_2}]}^{5/2}}}} = \frac{{{K_2}K_3^3}}{{{K_1}}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 6.1. Equilibrium - 1 (chemical Equilibrium)→6.1. Equilibrium - 1 (chemical Equilibrium) — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

For the fuel cell reaction

$2H_2(g) + O_2(g) \to 2H_2O(l)$  ;     $\Delta _fH^o_{298}(H_2O(l)) = -285.5\, kJ/mol$

What is $\Delta S^o_{298}$ for the given fuel cell reaction ?

Given $: O_2(g) + 4H^+(aq) + 4e^- \to  2H_2O(l)$   $E^o = 1.23\, V$

→
The number of waves made by a Bohr electron in an orbit of maximum magnetic quantum number $3$ is
→
The order of filling of electrons in the orbitals of an atom will be
→
Assign $A, B, C, D$ from given type of reaction. $N{H_4}Cl + NaN{O_2}\xrightarrow{\Delta }{N_2} \uparrow  + NaCl + {H_2}O$
→
The number of correct statements from the following

$A.$ For 1 s orbital, the probability density is maximum at the nucleus.

$B.$ For $2 s$ orbital, the probability density first increases to maximum and then decreases sharply to zero.

$C.$ Boundary surface diagrams of the orbitals encloses a region of $100 \%$ probability of finding the electron.

$D.$ $p$ and d-orbitals have $1$ and $2$ angular nodes respectively.

$E.$ Probability density of p-orbital is zero at the nucleus.

→
An electron has a spin quantum number $+1/2$ and magnetic quantum number $-1.$ It cannot be present in :
→
On complete combustion $0.30 \,g$ of an organic compound gave $0.20\, g$ of carbon dioxide and $0.10\, g$ of water. The percentage of carbon in the given organic compound is $.....$ (Nearest Integer)
→
Identify the wrongly match pair.
Molecule $\quad$ $\quad$ Shape or geometry of molecule
→
Find the energy of the photons which correspond to light of frequency $3 \times 10^{15} Hz$ (Hint: $h =$ Planck's constant$
\left.=6.626 \times 10^{-34} Js\right) ?
$
→
Benzene is prepared in laboratory from which one of the following compounds
→