
- A

- B

- ✓

- D








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Sucrose $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ Glucose $\quad$ Fructose
$C _{6} H _{12} O _{6} \stackrel{\text { Enzyme B }}{\longrightarrow} 2 C _{2} H _{5} OH +2 CO _{2}$
Glucose
In the above reactions, the enzyme $A$ and enzyme $B$ respectively are :-
$C{{H}_{3}}CN+2H\underset{\text{Ether}}{\mathop{\xrightarrow{HCl}}}\,X\underset{{{H}_{2}}O}{\mathop{\xrightarrow{\text{Boiling}}}}\,Y;$ the term $Y$ is:
$\begin{array}{*{20}{c}}
{C{H_3} - CH = C - C{H_2} - C{H_3}} \\
{|\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2} - C{H_2} - C{H_3}}
\end{array}$
$(a)$ tetraamminecobalt $(III)$ dim-hydroxidotetra amminecobalt $(III)$ ion
$(b)$ di $-\mu -$ hydroxidobis(tetraammine)dicobalt $(III)$
$(c)$ Bis $-(\mu -$ hydroxidotetraamminecobalt $(III))$
$(d)$ di $-\mu-$ hydroxidooctaamminedicobalt $(III)$
correct option is