The force is given in terms of time t and displacement x by the equation {F}={A} cos {Bx}+{C} sin {Dt} The dimensional formula of frac{{AD}}{{B}}

Q: The force is given in terms of time $t$ and displacement $x$ by the equation ${F}={A} \cos {Bx}+{C} \sin {Dt}$ The dimensional formula of $\frac{{AD}}{{B}}$ is -

a $\theta$ of cos or sin should be dimensionless. ${[ A ]=\left[ MLT ^{-2}\right] }$ ${[ B ]=\left[ L ^{-1}\right] }$ ${[ D ]=\left[ T ^{-1}\right] }$ ${\left[\frac{ AD }{ B }\right]=\frac{\left[ MLT ^{-2}\right]\left[ T ^{-1}\right]}{\left[ L ^{-1}\right]} }$ ${\left[\frac{ AD }{ B }\right]=\left[ ML ^{2} T ^{-3}\right] }$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

The force is given in terms of time $t$ and displacement $x$ by the equation

${F}={A} \cos {Bx}+{C} \sin {Dt}$

The dimensional formula of $\frac{{AD}}{{B}}$ is -

A$\left[{ML}^{2} {T}^{-3}\right]$
B$\left[{M}^{2} L^{2} {T}^{-3}\right]$
C$\left[{M}^{1} {L}^{1} {T}^{-2}\right]$
D$\left[{M}^{0} {LT}^{-1}\right]$

JEE MAIN 2021, Medium

STD 11 Science
JEE
STD 11 - 1. units,dimensions and measurement
Physics

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