Time (T), velocity (C) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions

Q: Time $(T)$, velocity $(C)$ and angular momentum $(h)$ are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be

a Let mass related as $M \propto \,{T^x}{C^y}{h^z}$ ${M^1}{L^0}{T^0} = {\left( T \right)^x}{\left( {{L^1}{T^{ - 1}}} \right)^y}{\left( {{M^1}{L^2}{T^{ - 1}}} \right)^z}$ ${M^1}{L^0}{T^0} = {M^z}{L^{y + 2z}} + {T^{x - y - z}}$ $z = 1$ $y + 2z = 0$ $x - y - z = 0$ $y = - 2$ $x + 2 - 1 = 0$ $M = \left[ {{T^{ - 1}}{C^{ - 2}}{h^1}} \right]$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

Time $(T)$, velocity $(C)$ and angular momentum $(h)$ are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be

A$\left[ M \right] = \left[ {{T^{ - 1}}\,{C^{ - 2}}\,h} \right]$
B$\left[ M \right] = \left[ {{T^{ - 1}}\,{C^2}\,h} \right]$
C$\left[ M \right] = \left[ {{T^{ - 1}}\,{C^{ - 2}}\,{h^{ - 1}}} \right]$
D$\left[ M \right] = \left[ {T\,{C^{ - 2}}\,h} \right]$

JEE MAIN 2017, Diffcult

STD 11 Science
JEE
STD 11 - 1. units,dimensions and measurement
Physics

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