The force required to punch a square hole $2\,cm$ side in steel sheet $2\,mm$ thick is (shearing stress of steel sheet $= 3.5\times 10^8\,\,N/m^2$ )
Medium
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Shearing stress will be on the area of boundary of hole
Area of this surface
$=4 \times\left(2 \times 10^{-2}\right) \times\left(0.2 \times 10^{-2}\right) \mathrm{m}^{2}=1.6 \times 10^{-4} \mathrm{m}^{2}$
$S_{\min }=3.5 \times 10^{8}=\frac{\mathrm{F}}{1.6 \times 10^{-4}} \Rightarrow \mathrm{F}=5.6 \times 10^{4} \mathrm{N}$
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