The force required to stretch a wire of crosssection $1 cm ^{2}$ to double its length will be ........ $ \times 10^{7}\,N$

(Given Yong's modulus of the wire $=2 \times 10^{11}\,N / m ^{2}$ )

JEE MAIN 2022, Easy
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$F =Y A \frac{\Delta l}{l}$

$=2 \times 10^{11} \times 10^{-4}\left(\frac{2 l-l}{l}\right)$

$=2 \times 10^{7}\,N$

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