a
(a)
At same value of load
$A$ has less elongation than $B \quad \ldots (1)$
$\frac{F L}{A Y}=\Delta L$ $\left\{\begin{array}{l}\because L, A \text { are same } \\ F \text { - Load is also taken same }\end{array}\right\}$
So $\frac{1}{Y} \propto \Delta L \quad \ldots (2)$
Using conditions $(1)$ and $(2)$
We can say
$Y_A > Y_B$ $\{$ Young's modulus of $A$ greater than $B\}$
