MCQ
The formula unit mass of $Ca _3\left( PO _4\right)_2$ is :
  • A
    $360$
  • B
    $240$
  • C
    $118$
  • $310$

Answer

Correct option: D.
$310$
Mass of $Ca _3\left( PO _4\right)_2$
$= (3 \times$ atomic mass of $Ca) + (2 \times $ atomic mass of phosphorus$) + (8 \times $ atomic mass of oxygen$)$
$=3 \times 40+2 \times 31+8 \times 16=310$

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