MCQ
The four arithmetic means between $3$ and $23$ are
- A$5, 9, 11, 13$
- ✓$7, 11, 15, 19$
- C$5, 11, 15, 22$
- D$7, 15, 19, 21$
So $3,\;{A_1},\;{A_2},\;{A_3},\;{A_4},\;23$
$ \Rightarrow $ ${T_6} = 23 = a + 5d$
$ \Rightarrow $ $d = 4$
Thus ${A_1} = 3 + 4 = 7,\;{A_2} = 7 + 4 = 11,\;$
$A_3 = 11+4 =15 ,\, A_4 = 15+ 4=19$
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is equal to :- (where $[.]$ greatest integer function)
| Variate $( x )$ | $x _{1}$ | $x _{1}$ | $x _{3} \ldots \ldots x _{15}$ |
| Frequency $(f)$ | $f _{1}$ | $f _{1}$ | $f _{3} \ldots f _{15}$ |
where $0< x _{1}< x _{2}< x _{3}<\ldots .< x _{15}=10$ and
$\sum \limits_{i=1}^{15} f_{i}>0,$ the standard deviation cannot be