MCQ
The four distinct points $(0, 0),(2, 0), (0, -2)$ and $(k,-2)$ are con-cyclic, if $k =$
- A$-2$
- ✓$2$
- C$1$
- D$0$
${x^2} + {y^2} - 2x + 2y = 0$.
If it passes through $(k,\, - 2)$, then ${k^2} + 4 - 2k - 4 = 0$
$ \Rightarrow \,k = 0,\,2$
$(0,\, - 2)$ is already a point on circle $\therefore $ $k = 2.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
