MCQ
The function $f(x) = \left\{ \begin{array}{l}x + 2\,\,\,\,,\,\,\,1 \le x \le 2\\4\,\,\,\,\,\,\,\,\,\,\,,\,\,\,x = 2\\3x - 2\,\,,\,\,\,x > 2\end{array} \right.$ is continuous at
  • A
    $x = 2$ only
  • B
    $x \le 2$
  • C
    $x \ge 2$
  • D
    None of these

Answer

Clearly the function is defined only in the interval $[1,\infty ]$
hence option $(b)$ cannot even apply.
For $x > 2,y = 3x - 2$ which is a straight line, hence continuous. 
Further $y = 4$ at $x = 2$.
Hence, the function is continuous at $x = 2$ also $($but not at $x = 2$ only $).$

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