Question
The function $f(x)=k \ x - \sin\ x$ is strictly increasing for

Answer

Given $, f(x)=k\ x-\sin x$
$\Rightarrow f^{\prime}(x)=k-\cos x>0 $
$\quad(\because f(x) \text { is strictly increasing } \therefore f(x)>0)$
$\Rightarrow k>\cos x$
$\therefore k>1 \quad (\because \cos x \in[-1,1])$

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