Question
The function $f(x)=x-\frac{1}{x}, x \in R, x \neq 0$ is

Answer

(a) : $f(x)=x-\frac{1}{x}$
$\therefore f^{\prime}(x)=1+\frac{1}{x^2}>0$ for all $x \in R, x \neq 0$
$\therefore \quad f(x)$ is increasing for all $x \in R$, where $x \neq 0$.

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