Question
The function ' $t$ ' which map temperature in Celsius $( C )$ into temperature in Fahrenheit $( F )$ is defined by $t ( C )= F$ where $F =\frac{9}{5} C +32$. Find, the temperature when the Celsius value is equal to the Fahrenheit value

Answer

Given $t(C)=\frac{9}{5} C+32$
consider the value of C be “x”
$t(C)=\frac{9}{5} C+32 $
$ x=\frac{9}{5} x+32$
$ 5 x=9 x+160$
$ -160=9 x-5 x$
$-160=4 x$
$ x=\frac{-160}{4}=-40$
The temperature when the Celsius value is equal to the fahrenheit value is $– 40^\circ$

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