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Relations and Functions — MATHS STD 10 — Question

Tamilnadu BoardEnglish MediumSTD 10MATHSRelations and Functions2 Marks
Question
The function ' $t$ ' which map temperature in Celsius $(C)$ into temperature in Fahrenheit $(F)$ is defined by $t(C)=F$ where $F=\frac{9}{5} C+32$. Find, the value of $C$ when $t(C)=212$
✓

Answer

$\text { Given } t(C)=\frac{9}{5} C +32 $
$ t( C )=212 $
$\frac{9}{5} C +32=212$
$ \frac{9}{5} C =212-32 $
$ =180 $
$ 9 C =180 \times 5 $
$C =\frac{180 \times 5}{9} $
$=100^{\circ} C$

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