Question
The function ' $t$ ' which map temperature in Celsius $(C)$ into temperature in Fahrenheit $(F)$ is defined by $t(C)=F$ where $F=\frac{9}{5} C+32$. Find, $t(-10)$
✓
Answer
$\text { Given } t(C)=\frac{9}{5} C +32$
$ t (-10)=\frac{9}{5}(-10)+32 $
$ =-18+32 $
$=14^{\circ} F$
$ t (-10)=\frac{9}{5}(-10)+32 $
$ =-18+32 $
$=14^{\circ} F$
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