MCQ
The function $y = a(1 - \cos x)$ is maximum when $x = $
- ✓$\pi $
- B$\pi /2$
- C$ - \pi /2$
- D$ - \pi /6$
==> $y' = 0 \Rightarrow \sin x = 0$ ==> $x = 0,\,\pi $
Now $y'' = a\cos x$ ==> $y''(0) = a$ and $y''(\pi ) = - a$
Hence $y$ is maximum when $x = \pi $.
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