MCQ
The general solution of ${x^2}\frac{{dy}}{{dx}} = 2$ is
- A$y = c + \frac{2}{x}$
- ✓$y = c - \frac{2}{x}$
- C$y = 2cx$
- D$y = c - \frac{3}{{{x^2}}}$
Now integrate it.
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$(A)$ $f(x)$ is continuous at $x=-\frac{\pi}{2}$
$(B)$ $f(x)$ is not differentiable at $x=0$
$(C)$ $f(x)$ is differentiable at $x=1$
$(D)$ $ f(x)$ is differentiable at $x=-\frac{3}{2}$