MCQ
The given figure represents two isobaric processes for the same mass of an ideal gas, then
- A$P_2 \geq P_1$
- B$P_2>P_1$
- C$P_1=P_2$
- ✓$P_1>P_2$
✓
Answer
Correct option: D.
$P_1>P_2$
d
$\mathrm{PV}=\mathrm{nRT}$
$\mathrm{PV}=\mathrm{nRT}$
$\mathrm{V}=\left(\frac{\mathrm{nR}}{\mathrm{P}}\right)_{\mathrm{T}}$
$\text { Slope }=\frac{\mathrm{nR}}{\mathrm{P}}$
$\text { Slope } \propto \frac{1}{\mathrm{P}}$
$(\text { Slope })_2>(\text { Slope })_1$
$\mathrm{P}_2<\mathrm{P}_1$
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