Question
The graph between the stopping potential $\left( V _{ o }\right)$ and frequency $(v)$ for two different metal plates P and Q are shown in the figure. Which of the metals has greater work function and why?
Image

Answer

Metal Q has a greater work function. Reason: The graph shows that the threshold frequency $\left(\nu_0\right)$ for metal Q is higher than that for metal P. Since work function $\Phi=h \nu_0$, a higher threshold frequency implies a greater work function.

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