The graph of an object's motion (along the x- axis) is shown in t… - Vidyadip

MCQ

The graph of an object's motion (along the $x-$ axis) is shown in the figure. The instantaneous velocity of the object at points $A$ and $B$ are $v_A$ and $v_B$ respectively. Then

✓
$v_A = v_B = 0.5\,m/s$
B
$v_A = 0 .5\,m/s < v_B$
C
$v_A = 0 .5\,m/s > v_B$
D
$v_A = v_B = 2\,m/s$

✓

Answer

Correct option: A.

$v_A = v_B = 0.5\,m/s$

a
$\begin{array}{l}
{\rm{ Instan}}{\kern 1pt} {\rm{tan}}eous\,velocity\,v = \frac{{\Delta x}}{{\Delta t}}\\
From\,graph,\,{v_A} = \frac{{\Delta {x_A}}}{{\Delta {t_A}}} = 0.5m/s\\
and\,{v_B} = \frac{{\Delta {x_B}}}{{\Delta {t_B}}} = \frac{{8m}}{{16s}} = 0.5m/s\\
i.e.,{v_A} = {v_B} = 0.5m/s
\end{array}$

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