MCQ
The ground state energy of hydrogen atom is $-13.6\, eV$. The energy of second excited state of $He^+$ ion in $eV$ is
- A$-54.4$
- B$-3.4$
- ✓$-6.04$
- D$-27.2$
✓
Answer
Correct option: C.
$-6.04$
c
$E = - 13.6\frac{{{n^2}}}{{{z^2}}}\,eV$
$E = - 13.6\frac{{{n^2}}}{{{z^2}}}\,eV$
$E_{He}^ + = - 13.6\frac{4}{9}$
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