MCQ
The group of molecules having identical shape is
- A$PCl_5,\,IF_5,\, XeO_2F_2$
- B$BF_3,\,PCl_3,\,XeO_3$
- C$SF_4,\,XeF_4,\,CCl_4$
- ✓$ClF_3,\, XeOF_2,\, XeF_3^+$
✓
Answer
Correct option: D.
$ClF_3,\, XeOF_2,\, XeF_3^+$
d
$Cl{I_3} \to $ Hybridisation $ = 3 + \frac{1}{2}[7 - 3] = 5\,(s{p^3}d)$
$Cl{I_3} \to $ Hybridisation $ = 3 + \frac{1}{2}[7 - 3] = 5\,(s{p^3}d)$
$XeOF_2 \to $ Hybridisation $ = 3 + \frac{1}{2}[8 - 4] = 5\,(s{p^3}d)$
$XeF_3^+ \to $ Hybridisation $ = 3 + \frac{1}{2}[8 - 3 - 1] = 5\,(s{p^3}d)$
All molecules have $sp^3d$ hybridization and $2$ lone pairs. Hence all have identical ( $T-$ shape).
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