MCQ
The heat evolved in the combustion of methane is given by the following equations:$C{H_4}(g) + 2{O_2}(g)\, \to \,C{O_2}(g) + {H_2}O(l);$$\Delta H = - 890.3\,kJ$ How many grams of methane would be required to produce  $445.15\, kJ$  of heat of combustion......$g$
  • A
    $4 $
  • $8$
  • C
    $12$
  • D
    $16$

Answer

Correct option: B.
$8$
(b) $C{H_4}$ required $ = \frac{{445.15 \times 16}}{{890.3}} = 8\,gm$.

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