MCQ
The heat of combustion of ethylene $C_2H_4(g)$ is $-1420\,kJ/mole$ . The number of litres of $C_2H_4$ at $NTP$ that would evolve $355\,kJ$ on combustion is
- A$2.8$
- B$8.4$
- ✓$5.6$
- D$11.2$
✓
Answer
Correct option: C.
$5.6$
c
$C _2 H _4+3 O _2 \longrightarrow 2 CO _2+2 H _2 O \quad \Delta H =1420\, kJ / mole$
$C _2 H _4+3 O _2 \longrightarrow 2 CO _2+2 H _2 O \quad \Delta H =1420\, kJ / mole$
$1420 \,kJ$ energy is released by $1\, mole$ of ethylene.
Given; heat evolved $=355\, kJ$
$\therefore$ No. of Liter $=\frac{355}{1420} \times 22.4 \,lt$
$=5.6 \,liter$
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