MCQ
The heat of hydrogenation for $3$ -methylbutene and $2$ -pentene are $-30\, kcal/mol$ and $-28\,kcal/mol$ respectively. The heats of combustion of $2$ -methylbutane and  pentane are - $784 \,kcal / mol$ and $-782 \,kcal/mol$ respectively. All the values are  given under standard conditions. Taking into account that combustion of both alkanes  give the same products, what is $\Delta H$ (in $kcal/mol$) for the following reaction under  same conditions ?
  • A
    $0$
  • $-4$
  • C
    $-2$
  • D
    $2$

Answer

Correct option: B.
$-4$
b
$\Delta H_1 = -30\, kcal/mol$ , $\Delta H_2 = (-784 + 782) \,kcal/mol$ , $\Delta H_3 = 28\, kcal/mol$
$\Rightarrow \Delta H_1 + \Delta H_2 + \Delta H_3 = - 4 \,kcal /mol$

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