MCQ
The highest oxidation state shown by transition elements is
- A$+ 7$ by $Mn$
- B$+ 8$ by $Os$
- C$+ 8$ by $Ru$
- ✓Both $(b)$ and $(c)$
Hence Options $\mathrm{B} \& \mathrm{C}$ are correct.
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$(CH_3)_2CHCH_2C \equiv N \xrightarrow{HCl,{{H}_{2}}O}$ compound $A \xrightarrow[2.\,{{H}_{2}}O]{1.\,LiAl{{H}_{4}}}$ compound $B \xrightarrow[C{{H}_{2}}C{{l}_{2}}]{PCC}$ compound $C$
Given : $Cr _2 O _7^{2-} \rightarrow Cr ^{3+} ; E ^0=1.330\,V$ and
$\frac{2.303 RT }{ F }=0.059\,V$
The potential for the half cell reaction is $x \times 10^{-3}\,V$. The value of $x$ is $........$
Reason : $F$ has high electron affinity than $Cl$.