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3.2 , motion in plane — Physics STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 SciencePhysics3.2 , motion in plane1 Mark
MCQ
The horizontal range and maximum height attained by a projectile are $R$ and $H$, respectively. If a constant horizontal acceleration $a=g / 4$ is imparted to the projectile due to wind, then its horizontal range and maximum height will be
  • A
    $(R+H), \frac{H}{2}$
  • B
    $\left(R+\frac{H}{2}\right), 2 H$
  • C
    $( R +2 H ), H$
  • ✓
    $(R+H), H$
✓

Answer

Correct option: D.
$(R+H), H$
d
(d)

$H=H$ (as vertical component of acceleration has not changed)

$R^{\prime} =u_x T+\frac{1}{2} a_x T^2$

$=R+\frac{1}{2} \times \frac{g}{4} \times \frac{4 u^2 \sin ^2 \theta}{g^2}$

$=R \frac{u^2 \sin ^2 \theta}{2 g}=(R+H)$

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