MCQ
The hydrogen bond strength will be highest for
- A$O - H - O$
- B$F - H - O$
- C$O - H - F$
- ✓$F - H - N$
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$C{H_3}CHBrC{H_2}C{H_3}\xrightarrow{{alc.\,KOH}}$
$(i)$ $C{H_3}CH = CHC{H_3}$ (major product)
$(ii)$ $C{H_2} = CHC{H_2}C{H_3}$ (minor product)
$HCHO\xrightarrow[{dil{H_2}S{O_4}}]{{NaCN}}A\xrightarrow[{\operatorname{P} t}]{{{H_2}}}B$ The product $(B)$ is