- A$PH _3$ shows lower proton affinity than $NH _3$.
- B$PF _3$ exists but $NF _5$ does not.
- C$NO _2$ can dimerise easily.
- ✓$SO _2$ can act as an oxidizing agent, but not as a reducing agent.
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$(I)\, s-$ orbital of $A$ and $P_x$ -orbital of $B$
$(II)\, s-$ orbital of $A$ and $P_z$ orbital of $B$
$(Ill)\, p_y$ -orbital of $A$ and $p_z$ orbital of $B$
$(IV)\, s-$ orbital of both $(A)$ and $(B)$
$Ag\left( s \right)\left| {AgBr\left( s \right)\,\left| {B{r^ - }\left( {0.01\,M} \right)} \right|\,\left| {{I^ - }\left( {0.02\,M} \right)} \right|\,AgI\left( s \right)} \right|Ag\left( s \right)$
the correct information is
[Given : $K_{sp}\,\left( {AgBr} \right) = 4 \times {10^{ - 13}}$ ,
$K_{sp}\,\left( {AgI} \right)$ $ = 8 \times {10^{ - 17}},\frac{{2.303\,RT}}{F} = 0.06\,V,\,\log \,2 = 0.3]$
$2A{B_2}(g) \rightleftharpoons 2AB(g) + {B_2}(g)$