The increase in length on stretching a wire is $0.05\%$. If its Poisson's ratio is $0.4$, then its diameter
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(a) Poisson’s ratio$ = \frac{{{\rm{Lateral strain}}}}{{{\rm{Longitudinal strian}}}}$
$\therefore $ Lateral strain$ = 0.4 \times \frac{{0.05}}{{100}}$
So reduced by $0.02\%.$
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